m^2=18m

Solution for m^2=18m equation:

m^2=18m

We move all terms to the left:

m^2-(18m)=0

a = 1; b = -18; c = 0;
Δ = b2-4ac
Δ = -182-4·1·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-18}{2*1}=\frac{0}{2}
=0
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+18}{2*1}=\frac{36}{2}
=18
$